To design the dimensions of the fin to keep the temperature within safe tolerances.
reality check 8
1) Finite difference approximation
2) Robin boundary condition
3) Initial condition
Assume: 1) Size of a fin: dimensions \(2 \times 2 cm\), with \(1 mm\) thickness.
2) Power input: \(5W\) along the entire left edge (\(2 cm\)).
3) \(M = N = 10\) steps in the \(x\) and \(y\) directions.
4) \(K = 1.68W/cm°C\)(aluminum fin), \(H = 0.005W/cm2 °C\), \(u_b = 20 °C\).
Goal: Plot the resulting heat distribution over the xy-plane (Use the mesh command),
and determine the maximum temperature(°C) of the fin.
Matlab code: here
Result: Maximum temperature = 1.649356799942613e+02 °C
Assume: 1) Size of a fin: dimensions \(4 \times 4 cm\), with \(1 mm\) thickness.
2) Power input: \(5W\) along the interval \([0,2]\) on the left side (\(2 cm\)).
Goal: Plot the resulting heat distribution,
and find the maximum temperature(°C).
Experiment with increased values of M and N.
Matlab code: here
Result:
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N=M=10 maxT = 69.470375461811372 gap from N=100 = 2.7693 (3.83%) |
N=M=50 maxT = 71.898570423874901 gap from N=100 = 0.3411 (0.47%) |
N=M=100 maxT = 72.239674205733081 |
Assume: 1) Size of a fin: dimensions \(4 \times 4cm\), with \(1 mm\) thickness.
2) Power input: \(5W\) along the interval \([0,2]\) on the left side (\(2 cm\)).
Goal: Use a "for" loop to find the maximum temperature(°C) at some interval of power.
Compare the maximum temperature at each power
and select the highest power that keeps the maximum temperature below 80(°C).
Result: Maximum power that keeps the maximum temperature below 80(°C) = 5.79 W
Assume: 1) Size of a fin: dimensions \(4 \times 4cm\), with \(1 mm\) thickness.
2) Power input: \(5W\) along the interval \([0,2]\) on the left side (\(2 cm\)).
3) The thermal conductivity K=3.85 W/cm°C(copper fin)
Goal: Use a "for" loop to find the maximum temperature(°C) at some interval of power.
Compare the maximum temperature at each power
and select the highest power that keeps the maximum temperature below 80(°C).
Result: Maximum power that keeps the maximum temperature below 80(°C)
i) power input place \([0,2]\): 7.32W
ii) power input place \([1,3]\): 7.64W
Result: Aluminum fin vs. Copper fin
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K=1.68W/cm°C(aluminum fin) Power input 5W |
K=3.85 W/cm°C(copper fin) Power input 5W |
Assume: 1) Size of a fin: dimensions \(4 \times 4cm\),, with \(1 mm\) thickness.
2) Power input: \(5W\) along the interval \([0,2]\) on the left side (\(2 cm\)).
Goal: Use a nested "for" loop to find the maximum temperature(°C)
at some interval of power and some value of K. Compare the maximum temperature
at each power and select the highest power that keeps the
maximum temperature below 80(°C). Then plot a function of K vs. P.
Matlab code: here
Result: data
Assume: 1) Size of a fin: dimensions \(4 \times 4cm\), with \(1 mm\) thickness.
2) Power input: \(5W\) along the interval \([0,2]\) on the left side (\(2 cm\)).
3) The thermal conductivity K=3.85W/cm(°C)
4) The heat transfer coefficent \(H=0.1W/cm^2\)(°C)
Goal: Use a "for" loop to find the maximum temperature(°C) at some interval of power.
Compare the maximum temperature at each power
and select the highest power that keeps the maximum temperature below 80(°C).
Matlab code: here
Result: Maximum power that keeps the maximum temperature below 80(°C)= 36.75 W